(3x^2-7x-30)=(7x^2+9x)

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Solution for (3x^2-7x-30)=(7x^2+9x) equation: 



(3x^2-7x-30)=(7x^2+9x)

We move all terms to the left:

(3x^2-7x-30)-((7x^2+9x))=0

We get rid of parentheses

3x^2-7x-((7x^2+9x))-30=0



We calculate terms in parentheses: -((7x^2+9x)), so:

(7x^2+9x)

We get rid of parentheses

7x^2+9x

Back to the equation:

-(7x^2+9x)



We get rid of parentheses

3x^2-7x^2-7x-9x-30=0

We add all the numbers together, and all the variables

-4x^2-16x-30=0

a = -4; b = -16; c = -30;
Δ = b2-4ac
Δ = -162-4·(-4)·(-30)
Δ = -224
Delta is less than zero, so there is no solution for the equation

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